Question

Find the value of k for which the equation 9x^2+2kx+1=0have real roots

Answer 1

Answer:k = 3

Step-by-step explanation:

a=9,b=2k,c=1

∆=0 since roots are real and equal

∆=b^2-4ac

0 =2k^2-4×9×1

0=4k^2-36

36=4k^2

36/4=k^2

9=k^2

K=√9

K=3