Find the value of k for which the equation has equal roots xsquare-kx+9=0
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Answered by
1
Step-by-step explanation:
GIVEN EQUATION:
x²-Kx+9=0
In the question it is said that the equation has equal roots.
So, it's discriminant = Zero .
b²-4ac=0.
(-k)²-4(1)(9)=0
(-k)²-36=0
k²-36=0
k²=36
k = ±√36
k = ±6
HOPE IT HELPS !!
Answered by
2
Step-by-step explanation:
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