Question

find the value of k for which the equation has real and equal roots 2xsquare+kx+9/2=0​

Answer 1

Answer:

k =+6, _6

Step-by-step explanation:

this is a quadratic equation. axsquare+bx+c =0

for real & equal roots, we must have,

bsquare _4ac = 0

so, here a= 2,b=k,c=9/2

so, ksquare _ 4*2*9/2=0

ksquare_36 =0

ksquare =36

k =+_6

k = +6, _6