find the value of k for which the equation has real roots
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dishagaur748:
hey mate!! you have done solution for real and equal roots whereas question asks for real roots only
means
The Answer is k= - 9/2 . So roots are not real
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hey mate!!
here is your answer:
in equation kx^2-6x-2, a=k, b=-6 and c=-2
so, discriminant=b^2-4ac
d=(-6)^2-4(k)(-2)
d=36+8k
now, discriminant can be equal to zero or greater than zero as the equation has real roots.
in this equation the value of k can be -4,-3,-2,-1,0 or greater than it to make the d equal to 0 or greater than zero.
hope it helped!!
here is your answer:
in equation kx^2-6x-2, a=k, b=-6 and c=-2
so, discriminant=b^2-4ac
d=(-6)^2-4(k)(-2)
d=36+8k
now, discriminant can be equal to zero or greater than zero as the equation has real roots.
in this equation the value of k can be -4,-3,-2,-1,0 or greater than it to make the d equal to 0 or greater than zero.
hope it helped!!
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