Question

Find the value of k for which the equation have real roots : 2x + kx +3=0. with explination​

Answer 1

Answer:

given,

2x^2+Kx+3

here it is in the form ax^2+bc+C=0

here a=2, b=K, c=3

if it has two equal roots. then ∆=0

b^2-4ac=0

k^2-4(2)(3)=0

k^2-24=0

k^2=24

k=√24

k=2√6

Hope it helps you.

Answer 2

Answer:

2√ 6

Step-by-step explanation:

If 2x^2  +kx+3=0 has equal roots, then b^ 2 −4ac=0.

Here, a=2,b=k,c=3

x  2  +kx+3=0

b  2  −4ac=0

k  2  −4(2)(3)=0

k  2  =24

k=√ 24

= 2√ 6

hope it helps plz mark me as brainliest..............

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