Question

find the value of k for which the equation kx square + 6 X + 1 is equal to zero has equal roots​

Answer 1

The value of k is equal to 9.

Step-by-step explanation:

The given quadratic equation:

$kx^{2}$ + 6x + 1 = 0

Here, a = k, b = 6 and c = 1

To find, the value of k = ?

∴ D = $b^{2}$ - 4ac

= $6^2$ - 4(k)(1)

= 36 - 4k

The condition of equal roots.

D = 0

∴ 36 - 4k = 0

⇒ 4k = 36

⇒ k = 9

∴ The value of k = 9

Thus, the value of k is equal to 9.