Find the value of k for which the equation kx2+2x+1=0 has real and distinct roots
Answers
Answered by
2
if right plz mark me as brainliest
Attachments:
Answered by
1
2kx+2x+1=0
2x(k+1)+1=0
(2x+1)(k+1)=0
k=-1
2x(k+1)+1=0
(2x+1)(k+1)=0
k=-1
Similar questions