Question

Find the value of k for which the equation kx²-5x+khas real roots

Answer 1

Hey

Here is your answer,

kx²-5x+k=0

a = k
b = -5
c = k

b^2 - 4ac = (-5)^2 - 4 x k x k
25 - 4k^2 = 0
4k ^2 = 25
k^2 = 25/4
k^2 = √25/4
k = 5/2

Hope it helps you!