Question

Find the value of k for which the equation kx²+6x+1=0 has two equal roots

Answer 1

Answer:

k=9

Step-by-step explanation:

D=0(given)

b^2-4ac=0

b=6,

a=k and

c=1

therefore,

(6)^2-4(k)(1)=0

36-4k=0

-4k=-36

k=36/4

k=9

Answer 2

Answer:

For k < 9, the equation kx² + 6x + 1 = 0 has real roots.

Step-by-step explanation:

refer the attachment for your answer.

hope it helps

ana205