Question

Find the value of k for which the equation kx2 _kx+1=0

Answer 1

kx2 - kx + 1 = 0

D = b2 - 4ac                    ( a = k, b = - k, c = 1 )
  
    = ( - k ) square - 4 (k)(1)
      
    = k square - 4k
 
    = k ( k - 4 )
 
     k = 0 , k = +4          
 
"0" cannot be the value.
therefore the value of k is + 4.

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