Question

find the value of k for which the equation x^2+(1-2k)x+k^2-1=0 has only one real value of x as it's solution

Please give step-by-step solution as soon as possible.
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Answer 1

Answer:

Consider a general equation Ax^2 + Bx + C = 0 For this equation to have equal ... So, by applying the above condition we get, [(2(1+k)]^2 - 4*1*k^2 = 0, . ... If the equation x^2 + 2(1+k) x + k^2 = 0 has equal roots, then what is the value of k? ... If the roots of are equal in magnitude but opposite in sign, how can I show that and ...

Step-by-step explanation:

hope it helps.