Question

find the value of K for which the equation
x^2 - 2kx + k = 0 has equal roots​

Answer 1

Answer:

$x {}^{2} + 2kx + k = 0 \\ (1) {}^{2} + 2k(1) + k = 0 \\ 1 + 2k + k = 0 \\ 3k + k = 0 \\ 4k = 0 \\ k = - 4$

ok marks as brainliest☺