Question

find the value of k for which the equation x^2-4x+k=0 has equal roots

Answer 1

Solution is in the attachment..

Answer 2

हल- समीकरण


${x}^{2} - 4x + k = 0$

यहाँ

$a = 1 \: \: \: \: \: \: \: \: \: \: b = -4 \: \: \: \: \: \: \: \: \: \: c = k$


जब मूल बराबर होते हैं तब प्रतिबंध

${b}^{2} = 4ac \\ \\ \\ ( - 4) {}^{2} = 4 \times 1 \times k \\ \\ 4k = 16 \\ \\ \\ k = 4$