Find the value of k for which the equation x^2+k(2x+k-1)+2=0. has real and equal roots.
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x2+k(2x+k-1)+2=0
x2+2xk+2k-k+2=0
x2+2xk+k=-2
x2+2xk=-2/k
x2+2xk+2k-k+2=0
x2+2xk+k=-2
x2+2xk=-2/k
ankita123465:
thx
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