Question

find the value of k for which the equation x^2+kx+64=0has real roots.​

Answer 1

Answer:

16

Step-by-step explanation:

For a quadratic equation to have real roots, discriminant must be greater than or equal to zero.

For the first equation,

k²4(1)(64) ≥ 0 (. discriminant = b² - 4ac)

⇒ k² - 256> 0

⇒ (k − 16) (k+16) > 0

⇒k > 16 and k < -16 For the second equation,

64 - 4k > 0

⇒k<16

... the value of k that satisfies both the

conditions is k = 16.

Answer 2

Step-by-step explanation:

according to quartic formula

a= 2,b=k c =64

x=±√b²-4ac/2a

x=