Question

Find the value of k for which the equation x2 2(k 1)x k^2has real and equal roots

Answer 1

Answer:

Step-by-step explanation:

If the root of the equation x^2-4x+k=0 is 6, then what is the value of k?

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6 ANSWERS

Matt Grant

Matt Grant, Did well in high school math long ago, still uses some of it

Answered Jan 10, 2018

Substitute 6 for x, solve for k.

(6(6))2−4(6)+k=02−4(6)+k=0

36–24=−k36–24=−k

k=−12k=−12

Now, since this is a quadratic equation, 6 isn't the root, but rather a root. There are two. For bonus points, let’s find the other, now that we know k:

x2−4x−12=0x2−4x−12=0

(x+2)(x−6)=0(x+2)(x−6)=0

x=−2,6