Question

find the value of k for which the equation x2+5kx+16 has real and equal roots

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

For real and equal roots D=0

D=bsquare-4ac

Here,a=1,b=5kand c=16

(5k)square -4(1)(16)=0

25k square -64=0

Ksquare=64/25

K= underroot64/25

K=8/5

Step-by-step explanation: