find the value of k for which the equation x2+5kx+16 has real and equal roots
Answers
Answered by
4
Answer:
Step-by-step explanation:
Attachments:
Answered by
1
Answer:
For real and equal roots D=0
D=bsquare-4ac
Here,a=1,b=5kand c=16
(5k)square -4(1)(16)=0
25k square -64=0
Ksquare=64/25
K= underroot64/25
K=8/5
Step-by-step explanation:
Similar questions
History,
7 months ago
Physics,
7 months ago
Social Sciences,
7 months ago
Social Sciences,
1 year ago
Math,
1 year ago