Question

Find the value of k for which the equation x2+ k (2x + k -1) + 2 = 0 has real and equal roots.

Answer 1

Answer:

first of all mark me as a brainliest

then i will tell you the ans

Answer 2

Step-by-step explanation:

To find:

The value of k

Solution:

We can solve by using Discriminat .

What is discriminat ?

The discriminant is the part of the quadratic equation in which (coefficient of x)²- 4(coefficient of x²)(constant). The discriminant tells us whether there are two solutions, one solution, or no solutions.

When the quadratic equation have equal roots then the discriminant is equal to zero.

So,

Comparing the equation (k-5)²x²+2(k-5)x+2=0 from ax² + bx + c = 0, I get

a = (k-5) b=2(k-5) c = 2

Hence, The required value of k is 7.

please mark BRAINLIEST