Find the value of k for which the equation x2+ k (2x + k -1) + 2 = 0 has real and equal roots.
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Step-by-step explanation:
Quadratic Equations. Find the value of k for which the equation x2 + k(2x + k − 1) + 2 = 0 has real and equal roots. The given equation is x2+k(2x+k−1)+2=0. So, k = 2.
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Solution
⇒
The given quadratic equation
equation has equal roots, then the
the discriminan=
−k
,c=kThen, b2−4ac=0
valuue of k is 0,8
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