Find the value of k for which the equation x2+ k (2x + k -1) + 2 = 0 has real and equal roots.
Answers
Answered by
1
Step-by-step explanation:
sorry but the question seems to have some mistakes
x2+ k (2x + k -1) + 2 = 0 has real and equal roots.
Answered by
0
Step-by-step explanation:
Solution
⇒
The given quadratic equation is
2
x
2
−
k
x
+
k
=
0
⇒
If the equation has equal roots, then the discriminant
b
2
−
4
a
c
=
0.
⇒
Here,
a
=
2
,
b
=
−
k
,
c
=
k
Then,
b
2
−
4
a
c
=
0
(
−
k
)
2
−
4
(
2
)
(
k
)
=
0
k
2
−
8
k
=
0
k
(
k
−
8
)
=
0
∴
k
=
0
and
k
=
8
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