Question

. Find the value of k for which the equations kx-20y-6 = 0 and 6x-10y-14 = 0 has no solution.
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Answer 1

Answer:

here's explanation in attachment.

Answer 2

$\frac{a1}{a2}= \frac{b1}{b2}\neq \frac{c1}{c2}$

Step-by-step explanation:

• for 2 linear equation a1x+b1y+c1z=0 and a2x+b2y+c2z=0
• if $\frac{a1}{a2}= \frac{b1}{b2}\neq \frac{c1}{c2}$ then it has no solution
• therefore
• $\frac{k}{6}=\frac{20}{10}$
• k=2*6=12
• k should be 12 therefore the equations donot have no solution.