Math, asked by priyaram500, 3 months ago

find the value of k for which the following pair of equations have unique solution. (3k-2)x-ky+3=0,2kx+y-5=0

Answers

Answered by TanushreeKendle15

0

Answer:a1x+b1y+c1=0

a2x+b2y+c2=0

a1a1≠b1b2 unique solution

2k+3y+3=0

4x+y+4=0

2k4≠31

2k≠12

k≠6

k can have value energy=6.

Step-by-step explanation:

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