Math, asked by S123DFG, 11 months ago

Find the value of k for which the following pair of linear equation have infinitely many solution 2 X + 3 Y =7 ;(k-1)x +(k+2)y=3k

Answers

Answered by neha7254
3

hope u will like......

Attachments:

neha7254: plz mark me as brainliest
Answered by Anonymous
1

given equation

2x+3y=7

(k-1)x+(k+2)y=3k

for infinite many solution

 \frac{a1}{a2}  =   \frac{b1}{b2}  =  \frac{c1}{c2}

comparing this we get

 \frac{2}{k - 1}  =  \frac{3}{k + 2}  =  \frac{7}{3k}

 \frac{2}{k - 1}  =  \frac{3}{k + 2}....... \frac{7}{3k}   =  \frac{3}{k + 2}

2k + 4 = 3k - 3...........9k = 7k + 14

4 + 3 = 3k - 2k........9k - 7k = 14

7 = k........2k = 14

7 = k........k = 7

the value of k for which the given equation have infinite many solutions is

7

Similar questions