find the value of k for which the following pair of linear equation have no solutions 3x+y=2 (2k-1)x+(k-1)y=2k-1
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k=2
Step-by-step explanation:
the condition for no solution is a1/a2=b1/b2=c1/c2
here a1=3, b1= 1,c1=2
3/2k-1=1/k-1=2/2k-1
3(k-1) = 1(2k-1)
3k-2k-3+1=0
k-2=0
k=2
i hope i helped u a little bit
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