Find the value of k for which the following pair of linear equations have infinitely many solutions. 2x+3y=7,(k-1)x+(k+2)y=3k.
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for infinite solutions
a1/a2=b1/b2=c1/c2
here
2/k-1=3/k+2
k=7
putting k= 7
3/(k+2)=7/3k
since 7 satisfies here
so value of k=7
a1/a2=b1/b2=c1/c2
here
2/k-1=3/k+2
k=7
putting k= 7
3/(k+2)=7/3k
since 7 satisfies here
so value of k=7
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