Question

Find the value of k for which the following pair of linear equation have infinitely many solutions: 2x + 3y = 7; (k − 1) x + (k + 2)y = 3k

Answer 1

Let it would be infinite many solution
so :-
a1/a2 = b1/b2 = c1/c2

2x +3y = 7
(k - 1)x + (k + 2)y = 3k
2/k-1 = 3/k+2 = 7/3k
2/k-1 = 7/3k
6k = 7k -1
6k - 7k = -1
-k = -1
k = 1
3/k + 2 = 7/3k
9k = 7k + 14
9k - 7k = 14
2k = 14
k = 7

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Answer 2

Answer:

Step-by-step explanation: