Question

Find the value of k for which the following quadratic equation has real and equal roots (k+4)x^2+(k+1)x+1

Answer 1

Step-by-step explanation:

iff any quadratic equation has real nd equal roots,then it' s discriminant will be zero.

discriminant of an equation ax^2+ bx+ c= 0 having real nd equal roots is-

(bsquare -4 ac)=0.

here in the equation given by u discriminant will be-

(k+1)^2-4into 1 into (k+4)=0

solve this nd u will get the ans