Math, asked by vrushanknaik68, 4 months ago

Find the value of ‘k’ for which the following quadratic equation

has equal roots.

(k + 4) x2 + (k + 1) x + 1 = 0​

Answers

Answered by Anonymous
1

Answer:

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Step-by-step explanation:

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Answered by komalpatel000
0

(k+4)x2+(k+1)x+1=0

kx²+4x²+kx+x+1=0

kx²+kx+4x²+x+1=0

k(x²+x) +4x²+x+1=0

x²+x+4x²+x+1=0/k

5x²+2x+1=0

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