Find the value of ‘k’ for which the following quadratic equation
has equal roots.
(k + 4) x2 + (k + 1) x + 1 = 0
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(k+4)x2+(k+1)x+1=0
kx²+4x²+kx+x+1=0
kx²+kx+4x²+x+1=0
k(x²+x) +4x²+x+1=0
x²+x+4x²+x+1=0/k
5x²+2x+1=0
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