Question

Find the value of k for which the following system equations has no
solution KX-3 - 3y , 12x + 3y= 6.​

Answer 1

Answer:

The given system of equations:  kx + 3y = 3  kx + 3y - 3 = 0 ….(i)  12x + ky = 6  12x + ky - 6 = 0 ….(ii)  These equations are of the following form: a1x+b1y+c1 = 0, a2x+b2y+c2 = 0  where, a1 = k, b1= 3, c1 = -3 and a2 = 12, b2 = k, c2 = –6  In order that the given system has no solution, we must have: Hence, the given system of equations has no solution when k is equal to -6.Read more on Sarthaks.com - https://www.sarthaks.com/132161/find-the-value-of-k-for-which-the-system-of-equations-kx-3y-3-12x-ky-6-has-no-solution