Question

Find the value of k for which the following system of equation has no solution kx-y=2 and 6x-2y=3

Answer 1

answer is k = 3....
HOPE THIS WILL HELP YOU

Answer 2

Answer:

The value of k is $k=3$ and $k\neq4$

Step-by-step explanation:

Given : Equation $kx-y=2,6x-2y=3$

To find : The value of k for which the following system of equation has no solution.?

Solution :  

When the system of equation is in form $ax+by+c=0, dx+ey+f=0$ then the condition for no solutions is  

$\frac{a}{d}=\frac{b}{e}\neq \frac{c}{f}$

Compare and substituting the values,

$\frac{k}{6}=\frac{-1}{-2}\neq \frac{-2}{-3}$

$\frac{k}{6}=\frac{1}{2}\neq \frac{2}{3}$

Taking 1, $\frac{k}{6}=\frac{1}{2}$

$2\times k=1\times 6$

$2k=6$

$k=3$

Taking 2, $\frac{k}{6}\neq \frac{2}{3}$

$3\times k\neq 2\times 6$

$3k\neq12$

$k\neq4$

Therefore, The value of k is $k=3$ and $k\neq4$