Question

Find the value of k for which the following system of equations
has infinite solutions: 4x + 2y - (K + 2) = 0 and 2x + y - 3 = 0​

Answer 1

Answer:

Hope it helps!!!

The answer is shown in figure

Answer 2

Answer: k=4

Step-by-step explanation:

• The given equations are 4x+2y-(k+2)=0 and 2x+y-3=0.
• $a_{1}=4,b_{1}=2,c_{1}=-(k+2), a_{2}=2,b_{2}=1 \ and \ c_{2}=-3$
• For the equations to have an infinite solution the required condition is $\frac{a_{1} }{a_{2} }=\frac{b_{1} }{b_{2} } =\frac{c_{1} }{c_{2} }$.
• Let us consider $\frac{b_{1} }{b_{2} } =\frac{c_{1} }{c_{2} }$

                               ⇒$\frac{2}{1}=\frac{-(k+2)}{-3}$

                               ⇒6=k+2

                               ⇒k=6-2

                               ∴ k=4.

• Hence, the value of k for which the given equations has infinite solution is 4.

#SPJ2