find the value of k for which the following system of equation 4 x + K Y + 5 equal to zero and 2 X + 3 Y + 7 equal to zero exactly one solution
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Your answer will be -3 if you take x= -2 and y= -1
fahimhf7:
Can you give me the solution
Yes
by trial and error method for the equation 2x+3y+7=0
Then let’s take x=-2 and y=-1 for the above equation
2(-2)+3(-1)+7=0
-4-3+7=0
-7+7=0
0=0
x=-2 and y=-1 satisfies the above equation . So let’s take the value of x and y as -2,-1 respectively
Substitute the vale of x and y in the equation 4x+KY+5=0
So
4(-2)+k(-1)+5=0
-8-k=-5
k=5-8
K=-3
Then let’s take x=-2 and y=-1 for the above equation
2(-2)+3(-1)+7=0
-4-3+7=0
-7+7=0
0=0
x=-2 and y=-1 satisfies the above equation . So let’s take the value of x and y as -2,-1 respectively
Substitute the vale of x and y in the equation 4x+KY+5=0
So
4(-2)+k(-1)+5=0
-8-k=-5
k=5-8
K=-3
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