Question

Find the value of K for which the following system
of linear equations has no solution: 3x + 2y = 1, (2k+1)x + (k+2)y = k + 1​

Answer 1

Answer:

3x+2y=1,(2k+1)+(k+2)y=k+1

6xy=(2k)+(2k)y=k+1

(2k)+(2k) cancelled this 2k=6xy+y=k+1

6y+(k+1)

K+1=6x

k+x=1+6

K=7x

Step-by-step explanation: