Question

Find the value of k for which the following systems
of linear equations has an infinite number of solutions
2x+3y = 7,
(k-1)x + (K+2)y=3K.​

Answer 1

Answer:

0

Step-by-step explanation:

If 2x + 3y =7

then , x = 2

y = 1

so , by this :-

(k-1)2+(k+2)1=3k

2k-2+k+2=3k

3k=3k

3k-3k=0

0=0

and then if we check it

(0-1)2+(0+2)1=3(0)

(-1)2+(2)1=0

-2+2=0

0=0