Question

find the value of k for which the followingpairs of linear equations have no solution ;-
1.kx+3y=k-2
12x+ky=k

2. (K + 1 )X + 2y=5
3x + ky=7

3. 3x +y-1
(2x-1)x+(k-1)y=2k+1

Answer 1

1. k/12=3/k
36=k²
6=k
k=6



2.(k+1)/3=2/k
6=k²+k
k²+k-6=0
k²+3k-2k-6
k(k+3) -2(k+3)
(k+3) (k-2)
a. k+3=0
k=-3
b. k-2=0
k=2