Question

find
the value of K for which the
for which the quadratic
equation (k+u) x² + (k+ 1) x + 1 = 0​

Answer 1

Answer:

Given (k+1)x

2

−2(k−1)x+1=0 has equal roots

⟹Discriminant=0

⟹(−2(k−1)) 2−4(k+1)=0

⟹4(k 2−2k+1)−4k−4=0

⟹k2−3k=0⟹k=0,3

Hope it will help u