Question

Find
the value of k for which the given equation
has
equal roots.
(K-12) x² + 2 (K-12) x + 2 =0
​

Answer 1

Answer:

12

Step-by-step explanation:

may be it is write answers

Answer 2

Answer:

K-12) x² + 2 (K-12) x + 2 =0

given it has equal roots so b²-4ac=O

(2(k-12))²-4(k-12)(2)=0

4(k²+144-24k)-8(k-12)=0

4k²+576-96k-8k+96=0

4k²-104k+672=0

k²-26k+168=0

K=12,14