Question

Find the value of k for which the given equation has equal roots

(k-12) x2+2(k-12)x+2=0

Answer 1

for equal roots
b^2-4ac=0
[2(k-12)]^2-4(k-12)*2=0
4(k-12)[(k-12)-2]=0
(k-12)(k-14)=0
k=12,14
but k cant be 12
k=14