Question

find the value of k for which the given equation has real and equal roots second X Into (X - 2) close + 6 equal to zero​

Answer 1

Step-by-step explanation:

the given equation can be written in the form of

k {x}^{2} - 2kx + 6 = 0

now it has equal roots that means The Discriminant is 0

D = 0

Also

{b}^{2} - 4ac = 0 \\ {4k}^{2} - 4(k)(6) = 0 \\ 4 {k}^{2} - 24k = 0 \\ 4k(k - 6) = 0 \\ k - 6 = 0 \\ k = 6

Hence the value of K is 6.

HOPE IT HELPS

Answer 2

Answer:

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