Question

Find the value of K for which the given equation has real & equal roots : 2x² + 3x + K = O . 

a) 1/8

b)- 9/8

c) 9/8

d)0
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Answer 1

Answer:

9/8

Step-by-step explanation:

Comparing 2x² + 3x + k = 0 with ax²+bx+c=0

We get a=2 , b= 3 and c=k.

Discriminant

= b² - 4ac

= (3)² -4×2×k

= 9 -8k.

But roots are real and equal.

Thus, Discriminant = 0

Therefore,

9-8k =0

8k=9

k=9/8.

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Answer 2

$\bf{\underline{Question:-}}$

Find the value of K for which the given equation has real & equal roots : 2x² + 3x + K = O . 

a) 1/8

b)- 9/8

c) 9/8

d) 0

$\bf{\underline{Formula:-}}$

• Discriminant (D) = b² - 4ac

$\bf{\underline{Here:-}}$

• a = 2
• b = 3
• c = k

$\bf{\underline{Now:-}}$

• ⏩ Substituting the value of a , b , c in formula

$\bf{\underline{Solution:-}}$

$\sf → b^2-4ac=0$

$\sf→ 3^2 - 4×2×k=0$

$\sf → 9 - 8k=0$

$\sf → 9 = 8k$

$\sf → \frac{9}{8} = k$

$\bf{\underline{Hence:-}}$

• Value of k is 9/8