Question

find the value of k for which the given equation has real and equal roots : 2x^2 - 10x + k=0......please answer fast

Answer 1

2x^2-10x+k=0
a=2,b=-10,c=k
D=b^2-4ac
D=(-10)^2-4 (2)(k)
D=100-8k
100=8k
k=100/8......

Answer 2

2x²-10x+k=0
D=0
0=b²-4ac
0= (-10)² -4(2)(k)
0= 100-8k
8k=100
K=100/8
K=25/2