Question

find the value of k for which the given equation has real and equal roots:(k-12)x2+2(k-12)x+2=0

Answer 1

D=b^2-4ac
《2(k-12)^2 -4(k-12)(2)=0
4 (k^2-24)-4 (2k-24)=0
4k^2-96-8k+96=0
4k^2 -8k =0
4k (k-2)=0
k=-1