Find the value of k for which the given pair of equations have infinite many solutions
3x + 2y = 1; (2k + 1)x + (k + 2)y= K -1
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Step-by-step explanation:
first solve a1/a2 = b1/b2 and find k
then solve b1/b2 = c1/c2
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Answer:
Therefore the value of x is 4
Hope help u
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