Question

Find the value of k , for which the given pair of linear equations has a unique solution: 2x+ 3y-5=0 , kx- 6y -8=0

Answer 1

Answer:

Your answer is in the given attachment...

Step-by-step explanation:

℘ℓḙᾰṧe ՊᾰԻк Պḙ ᾰṧ ♭Իᾰ!ℵℓ!ḙṧт ✌✌✌

Answer 2

Answer:

k ≠ - 4

Step-by-step explanation:

Given :

Equation of lines :

2 x + 3 y - 5 = 0

k x - 6 y - 8 = 0

We're asked to find value of ' k ' for unique solution :

For unique solution we know :

a₁ / a₂ ≠ b₁ / b₂

= > 2 / k ≠ 3 / - 6

= > 2 / k ≠ - 1 / 2

= > 2 × 2 ≠ - k

= > k ≠ - 4

Therefore , value of ' k ' shouldn't equal to - 4 for unique solution!