Find the value of k for which the given pair of linear equations has no solution.
4x+ky=5
8x +12y= -10
Answers
Answered by
1
Step-by-step explanation:
Given that the pair of linear equation has no solution.
Therefore,
a1/a2 = b1/b2
a1=4 and a2=8
b1=k and b2 =12
a1/a2 = b1/b2
4/8 = k/12
1/2 = k/12
2k = 12
k= 12/2
k = 6
Similar questions