Question

Find the value of K for which the given series is in A.P  4, k-1, 12.​

Answer 1

Answer:

Step-by-step explanation:

The AP is 4 , k - 1 , 12

Arithmetic mean = 2b = a + c

Here :  a = 4 , b = k - 1 , c = 12

substituting the values of a , b , and c

2 (k - 1 ) = 4 + 12

2k - 2 =  16

2k = 16 + 2

2k = 18

k = 18/2

k = 9

Answer 2

Answer:

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