Math, asked by roshanshaikh76, 1 year ago

Find the value of k for which the given simultaneous equations have infinitely many solutions
k+ 4y = 10; 3x + 2y = 5.​

Answers

Answered by jindalkaran671
4

Answer:

for infinite many solutions

K/3=4/2=10/5

K/3=2

K=6

Answered by akshithaakki450
1

Answer:

k=6

Step-by-step explanation:

K÷ 3=4÷2

cross multiplication

2k= 4×3

k= 6

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