Find the value of k for which the given simultaneous equations have infinitely many solutions
k+ 4y = 10; 3x + 2y = 5.
Answers
Answered by
4
Answer:
for infinite many solutions
K/3=4/2=10/5
K/3=2
K=6
Answered by
1
Answer:
k=6
Step-by-step explanation:
K÷ 3=4÷2
cross multiplication
2k= 4×3
k= 6
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