Math, asked by aloksaw512, 1 year ago

Find the value of k for which the given system of equation has I infinitely many solution
x+(K+1)y=5
(k+1)x+9y+(1-8K)=0​

Answers

Answered by guptasidd1707
2

1/k+1 = k+1/9

9 = k² + 1 +2k

k² +2k -8 =0

k² +4k -2k -8 = 0

k(k+4) -2(k+4)= 0

k = 2, -4 ..........(1)

k+1/9 = 5/-1+8k

7k +8k² -1 = 45

8k² + 7k-46=0

so k =

Answered by indiravalar3
15

hope it helps you

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guptasidd1707: ya mark him as brainliest
indiravalar3: him???..
indiravalar3: helloo.....Im a girl
aloksaw512: Thanks you
indiravalar3: thank you for brainliest
aloksaw512: Hmmmm
guptasidd1707: oh sorry im very sorry didnt notice
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