Find the value of k for which the given system of equation has I infinitely many solution
x+(K+1)y=5
(k+1)x+9y+(1-8K)=0
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Answered by
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1/k+1 = k+1/9
9 = k² + 1 +2k
k² +2k -8 =0
k² +4k -2k -8 = 0
k(k+4) -2(k+4)= 0
k = 2, -4 ..........(1)
k+1/9 = 5/-1+8k
7k +8k² -1 = 45
8k² + 7k-46=0
so k =
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