Question

Find the value of k for which the given system of equation has no solution: kx+3y=k-3 and 12x+ky=k

Answer 1

Answer:

=kx-k+3y=-3

k(x-1)=-3y-3

k=-3y-3/x-1

then

12x=k-ky

12x=k(1-y)

k=12x/1-y

Step-by-step explanation:

Answer 2

Answer: -6

Step-by-step explanation:

if they has no solution

k/12 =3/k and it is not equal to (k-3)/k

k*k=3*12  and     3/k  is not ( k-3)/k

k^2=36   and   3 is not k-3

k= 6 or -6 and      k is not 6

the only possible value of k is -6