Math, asked by rushi4865, 3 months ago

Find the value of K for which the given value is a solution of the given equation 7x²+Kx-3=0,x=⅔

Answers

Answered by muskanperween225
1

Answer:

k = -1/6

Step-by-step explanation:

7x^2+kx-3=0

7(2/3)^2+k*2/3-3=0

7*4/9+2k/3-3=0

28/9+2k/3-3=0

28+6k/9=3

28+6k=27

6k=27-28

6k= -1

k= -1/6

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